What is the inverse of (x^2+7x+13)/(x+4) ?

The inverse of (x^2+7x+13)/(x+4) is (-7+x+sqrt(x^2+2x-3))/2 ,(-7+x-sqrt(x^2+2x-3))/2

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inverse of (x^2+7x+13)/(x+4)

inverse

\frac{x ^{2} + 7 x + 13}{x + 4}

\frac{- 7 + x + x ^{2} + 2 x - 3}{2}, \frac{- 7 + x - x ^{2} + 2 x - 3}{2}

Solution steps

y = \frac{x ^{2} + 7 x + 13}{x + 4}

Replace

x

with

y

x = \frac{y ^{2} + 7 y + 13}{y + 4}

Solve for

y, x = \frac{y ^{2} + 7 y + 13}{y + 4}

\frac{- 7 + x + x ^{2} + 2 x - 3}{2}, \frac{- 7 + x - x ^{2} + 2 x - 3}{2}

f (x) = e^{2} + 1

f (x) = \frac{b ^{x} + b ^{- x}}{2}

f (x) = 2 - 5 - x

1 + e^{- t}

- 2 x - 4

What is the inverse of (x^2+7x+13)/(x+4) ?
The inverse of (x^2+7x+13)/(x+4) is (-7+x+sqrt(x^2+2x-3))/2 ,(-7+x-sqrt(x^2+2x-3))/2