What is the inverse of f(x)=sqrt(((3x-1))/(2x+1)) ?

The inverse of f(x)=sqrt(((3x-1))/(2x+1)) is (-1-x^2)/(2x^2-3)

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inverse of f(x)=sqrt(((3x-1))/(2x+1))

inverse

f (x) = \frac{( 3 x - 1 )}{2 x + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

Solution steps

y = \frac{3 x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{3 y - 1}{2 y + 1}

Solve for

y, x = \frac{3 y - 1}{2 y + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

f (x) = - 5 ln (x) - 3

y = \frac{2 x + 1}{3}

f (x) = 1 - \frac{3 x}{2}

f (x) = \frac{5}{3 x - 7}

f (x) = 3 + 1 0^{x + 3}

What is the inverse of f(x)=sqrt(((3x-1))/(2x+1)) ?
The inverse of f(x)=sqrt(((3x-1))/(2x+1)) is (-1-x^2)/(2x^2-3)