What is the inverse of f(x)=(1-x^2)^{1/2} ?

The inverse of f(x)=(1-x^2)^{1/2} is sqrt(-x^2+1),-sqrt(-x^2+1)

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inverse of f(x)=(1-x^2)^{1/2}

inverse

f (x) = (1 - x^{2})^{\frac{1}{2}}

- x^{2} + 1, - - x^{2} + 1

Solution steps

y = (1 - x^{2})^{\frac{1}{2}}

Replace

x

with

y

x = (1 - y^{2})^{\frac{1}{2}}

Solve for

y, x = (1 - y^{2})^{\frac{1}{2}}

- x^{2} + 1, - - x^{2} + 1

f (x) = 2 x^{\frac{5}{7}}

f (x) = \frac{( 5 - 2 x )}{4 x - 2}

y = (x + 1)^{3}

\frac{0.6 z}{( z - 0.5 ) ( z - 0.2 )}

f (x) = ln (\frac{( x - 2 )}{2})

What is the inverse of f(x)=(1-x^2)^{1/2} ?
The inverse of f(x)=(1-x^2)^{1/2} is sqrt(-x^2+1),-sqrt(-x^2+1)