What is the inverse of f(x)=11x^2+4 ?

The inverse of f(x)=11x^2+4 is sqrt((x-4)/(11)),-sqrt((x-4)/(11))

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inverse of f(x)=11x^2+4

inverse

f (x) = 11 x^{2} + 4

\frac{x - 4}{11}, - \frac{x - 4}{11}

Solution steps

y = 11 x^{2} + 4

Replace

x

with

y

x = 11 y^{2} + 4

Solve for

y, x = 11 y^{2} + 4

\frac{x - 4}{11}, - \frac{x - 4}{11}

f (x) = \frac{x + 6}{x}

f (x) = 8 arcsin (4 x)

\frac{3 x - 1}{2 - x}

f (x) = \frac{4 - x}{7}

f (x) = \frac{- 3}{2 x + 4}

What is the inverse of f(x)=11x^2+4 ?
The inverse of f(x)=11x^2+4 is sqrt((x-4)/(11)),-sqrt((x-4)/(11))