What is the inverse of f(x)=x^2+4x+18 ?

The inverse of f(x)=x^2+4x+18 is -2+sqrt(x-14),-sqrt(x-14)-2

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inverse of f(x)=x^2+4x+18

inverse

f (x) = x^{2} + 4 x + 18

- 2 + x - 14, - x - 14 - 2

Solution steps

y = x^{2} + 4 x + 18

Replace

x

with

y

x = y^{2} + 4 y + 18

Solve for

y, x = y^{2} + 4 y + 18

- 2 + x - 14, - x - 14 - 2

f (x) = (14 x - 13)^{2}

y = - x^{2} + 2 x + 2

\frac{2 x + 3}{7 x - 8}

- \frac{1}{x ^{2}}

f (x) = - lo g_{10} (x + 3) - 4

What is the inverse of f(x)=x^2+4x+18 ?
The inverse of f(x)=x^2+4x+18 is -2+sqrt(x-14),-sqrt(x-14)-2