What is the inverse of f(x)=-(x+1)^2+3 ?

The inverse of f(x)=-(x+1)^2+3 is sqrt(-x+3)-1,-sqrt(-x+3)-1

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inverse of f(x)=-(x+1)^2+3

inverse

f (x) = - (x + 1)^{2} + 3

- x + 3 - 1, - - x + 3 - 1

Solution steps

y = - (x + 1)^{2} + 3

Replace

x

with

y

x = - (y + 1)^{2} + 3

Solve for

y, x = - (y + 1)^{2} + 3

- x + 3 - 1, - - x + 3 - 1

f (x) = \frac{2 x - 3}{4 - x}

f (x) = (1 - x^{2})^{- \frac{1}{3}}

x^{2} - 36

f (x) = \frac{4 x - 2}{5}

f (x) = x (\frac{x}{2} + 0.5)

What is the inverse of f(x)=-(x+1)^2+3 ?
The inverse of f(x)=-(x+1)^2+3 is sqrt(-x+3)-1,-sqrt(-x+3)-1