What is the inverse of f(x)=15x^2-1 ?

The inverse of f(x)=15x^2-1 is sqrt((x+1)/(15)),-sqrt((x+1)/(15))

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inverse of f(x)=15x^2-1

inverse

f (x) = 15 x^{2} - 1

\frac{x + 1}{15}, - \frac{x + 1}{15}

Solution steps

y = 15 x^{2} - 1

Replace

x

with

y

x = 15 y^{2} - 1

Solve for

y, x = 15 y^{2} - 1

\frac{x + 1}{15}, - \frac{x + 1}{15}

f (x) = (x + 2)^{3} + 7

f (x) = 15 x^{2} + 1

f (x) = 15 x^{2} + 7

6 x^{5}

f (x) = \frac{1}{2 x - 2}

What is the inverse of f(x)=15x^2-1 ?
The inverse of f(x)=15x^2-1 is sqrt((x+1)/(15)),-sqrt((x+1)/(15))