What is the inverse of d/d 4x^4,x>= 0,x=5 ?

The inverse of d/d 4x^4,x>= 0,x=5 is \sqrt[4]{x/4},-\sqrt[4]{x/4}

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inverse of d/d 4x^4,x>= 0,x=5

inverse

\frac{d}{d} 4 x^{4}, x \geq 0, x = 5

4 \frac{x}{4}, - 4 \frac{x}{4}

Solution steps

d = \frac{d}{d} \cdot 4 x^{4}

Replace

x

with

d

x = \frac{x}{x} \cdot 4 d^{4}

Solve for

d, x = \frac{x}{x} 4 d^{4}

4 \frac{x}{4}, - 4 \frac{x}{4}

\frac{4}{ln ( x ^{2} - 1 )}

f (x) = x + 30

f (x) = \frac{6 - x}{3}

y = \frac{5}{x - 3} + 6

f (x) = x^{2} - 20

What is the inverse of d/d 4x^4,x>= 0,x=5 ?
The inverse of d/d 4x^4,x>= 0,x=5 is \sqrt[4]{x/4},-\sqrt[4]{x/4}