What is the inverse of log_{3}((x-1)^2) ?

The inverse of log_{3}((x-1)^2) is sqrt(3^x)+1,-sqrt(3^x)+1

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inverse of log_{3}((x-1)^2)

inverse

lo g_{3} ((x - 1)^{2})

3^{x} + 1, - 3^{x} + 1

Solution steps

y = lo g_{3} ((x - 1)^{2})

Replace

x

with

y

x = lo g_{3} ((y - 1)^{2})

Solve for

y, x = lo g_{3} ((y - 1)^{2})

3^{x} + 1, - 3^{x} + 1

y = - \frac{3}{5} x + \frac{7}{5}

\frac{2 - 3 x}{4}

f (x) = 12 - 0.5 x

f (x) = 3 x - 1 + x^{2}

f (x) = \frac{9 - x}{4 x}

What is the inverse of log_{3}((x-1)^2) ?
The inverse of log_{3}((x-1)^2) is sqrt(3^x)+1,-sqrt(3^x)+1