What is the inverse of 2pix^2+16pix ?

The inverse of 2pix^2+16pix is (-16pi+sqrt(256pi^2+8pix))/(4pi),(-16pi-sqrt(256pi^2+8pix))/(4pi)

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inverse of 2pix^2+16pix

inverse

2 π x^{2} + 16 π x

\frac{- 16 π + 256 π ^{2} + 8 π x}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π x}{4 π}

Solution steps

y = 2 π x^{2} + 16 π x

Replace

x

with

y

x = 2 π y^{2} + 16 π y

Solve for

y, x = 2 π y^{2} + 16 π y

\frac{- 16 π + 256 π ^{2} + 8 π x}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π x}{4 π}

f (x) = \frac{1}{2 x + 6}

f (x) = 3 x + 2 - 6

f (x) = 1.5 x + 16

f (x) = \frac{x}{7 x - 3}

\frac{n - 5}{2}

What is the inverse of 2pix^2+16pix ?
The inverse of 2pix^2+16pix is (-16pi+sqrt(256pi^2+8pix))/(4pi),(-16pi-sqrt(256pi^2+8pix))/(4pi)