What is the inverse of f(x)=-3(x+1)^2-2 ?

The inverse of f(x)=-3(x+1)^2-2 is sqrt(-(x+2)/3)-1,-sqrt(-(x+2)/3)-1

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inverse of f(x)=-3(x+1)^2-2

inverse

f (x) = - 3 (x + 1)^{2} - 2

- \frac{x + 2}{3} - 1, - - \frac{x + 2}{3} - 1

Solution steps

y = - 3 (x + 1)^{2} - 2

Replace

x

with

y

x = - 3 (y + 1)^{2} - 2

Solve for

y, x = - 3 (y + 1)^{2} - 2

- \frac{x + 2}{3} - 1, - - \frac{x + 2}{3} - 1

\frac{2 x + 4}{5}

arcsin (0.5)

f (x) = - x^{3} - 2

(x - 11)^{2}

What is the inverse of f(x)=-3(x+1)^2-2 ?
The inverse of f(x)=-3(x+1)^2-2 is sqrt(-(x+2)/3)-1,-sqrt(-(x+2)/3)-1