What is the inverse of f(x)=sqrt((x-5)/2)+1 ?

The inverse of f(x)=sqrt((x-5)/2)+1 is 2x^2-4x+7

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inverse of f(x)=sqrt((x-5)/2)+1

inverse

f (x) = \frac{x - 5}{2} + 1

2 x^{2} - 4 x + 7

Solution steps

y = \frac{x - 5}{2} + 1

Replace

x

with

y

x = \frac{y - 5}{2} + 1

Solve for

y, x = \frac{y - 5}{2} + 1

2 x^{2} - 4 x + 7

f (x) = - 8 - 3 x

\frac{S}{S ^{2} + 4 S + 5}

f (x) = \frac{5 x}{3 + 5}

f (x) = (x + 3)^{2} - 1, x \geq - 3

f (x) = 12 + 2 x - 2

What is the inverse of f(x)=sqrt((x-5)/2)+1 ?
The inverse of f(x)=sqrt((x-5)/2)+1 is 2x^2-4x+7