What is the inverse of f(x)=\sqrt[3]{-4x-10} ?

The inverse of f(x)=\sqrt[3]{-4x-10} is -(x^3+10)/4

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inverse of f(x)=\sqrt[3]{-4x-10}

inverse

f (x) = 3 - 4 x - 10

- \frac{x ^{3} + 10}{4}

Solution steps

y = 3 - 4 x - 10

Replace

x

with

y

x = 3 - 4 y - 10

Solve for

y, x = 3 - 4 y - 10

- \frac{x ^{3} + 10}{4}

f (x) = arccos (\frac{1}{2})

f (x) = 3 ln (2 x - x^{2})

f (x) = \frac{- x}{1 + x}

x + 13

f (x) = \frac{( x + 3 )}{2 x + 5}

What is the inverse of f(x)=\sqrt[3]{-4x-10} ?
The inverse of f(x)=\sqrt[3]{-4x-10} is -(x^3+10)/4