What is the inverse of f(x)=(7x-1/2)/(x+1/3) ?

The inverse of f(x)=(7x-1/2)/(x+1/3) is (-3-2x)/(6(-7+x))

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inverse of f(x)=(7x-1/2)/(x+1/3)

inverse

f (x) = \frac{7 x - \frac{1}{2}}{x + \frac{1}{3}}

\frac{- 3 - 2 x}{6 ( - 7 + x )}

Solution steps

y = \frac{7 x - \frac{1}{2}}{x + \frac{1}{3}}

Replace

x

with

y

x = \frac{7 y - \frac{1}{2}}{y + \frac{1}{3}}

Solve for

y, x = \frac{7 y - \frac{1}{2}}{y + \frac{1}{3}}

\frac{- 3 - 2 x}{6 ( - 7 + x )}

3 + x^{2} + tan (\frac{π}{2})

\frac{x + 2}{1 - x}

f (x) = \frac{2 x + 7}{3 x - 4}

\frac{x + 3}{x + 2}

x^{2} - 2 x - 48

What is the inverse of f(x)=(7x-1/2)/(x+1/3) ?
The inverse of f(x)=(7x-1/2)/(x+1/3) is (-3-2x)/(6(-7+x))