What is the inverse of f(x)=x^2+3x-3 ?

The inverse of f(x)=x^2+3x-3 is (-3+sqrt(4x+21))/2 ,(-3-sqrt(4x+21))/2

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inverse of f(x)=x^2+3x-3

inverse

f (x) = x^{2} + 3 x - 3

\frac{- 3 + 4 x + 21}{2}, \frac{- 3 - 4 x + 21}{2}

Solution steps

y = x^{2} + 3 x - 3

Replace

x

with

y

x = y^{2} + 3 y - 3

Solve for

y, x = y^{2} + 3 y - 3

\frac{- 3 + 4 x + 21}{2}, \frac{- 3 - 4 x + 21}{2}

f (x) = 14 x - 3

f (x) = \frac{6 x - 7}{6}

y = x^{2} + 9, x \geq 0

f (x) = 10 - 4 x^{3}

f (x) = \frac{( - 2 x + 5 )}{2 x + 3}

What is the inverse of f(x)=x^2+3x-3 ?
The inverse of f(x)=x^2+3x-3 is (-3+sqrt(4x+21))/2 ,(-3-sqrt(4x+21))/2