What is the domain of f(x)=(sqrt(3x-2))/(x^2-3x-4) ?

The domain of f(x)=(sqrt(3x-2))/(x^2-3x-4) is 2/3 4

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domain of f(x)=(sqrt(3x-2))/(x^2-3x-4)

domain

f (x) = \frac{3 x - 2}{x ^{2} - 3 x - 4}

\frac{2}{3} \leq x < 4 or x > 4

Interval Notation

[\frac{2}{3}, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{2}{3}

Find undefined (singularity) points:

x = 4, x = - 1

Combine real regions and undefined points for final function domain

\frac{2}{3} \leq x < 4 or x > 4

x^{6} (x - 3)^{5}

f (x) = \frac{10}{x + 2}

\frac{x + 7}{3} - 2

2 g - 17 k = 53

What is the domain of f(x)=(sqrt(3x-2))/(x^2-3x-4) ?
The domain of f(x)=(sqrt(3x-2))/(x^2-3x-4) is 2/3 <= x<4\lor x>4