What is the inverse of f(x)=13-x^2,x>= 0 ?

The inverse of f(x)=13-x^2,x>= 0 is sqrt(-x+13),-sqrt(-x+13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=13-x^2,x>= 0

inverse

f (x) = 13 - x^{2}, x \geq 0

- x + 13, - - x + 13

Solution steps

y = 13 - x^{2}

Replace

x

with

y

x = 13 - y^{2}

Solve for

y, x = 13 - y^{2}

- x + 13, - - x + 13

f (x) = \frac{x + 1}{5 x + 1}

f (x) = x^{2} + 4 x - 21

f (x) = \frac{x - 4}{2 x + 5}

f (x) = e^{x + 1} - 2

f (x) = - 7 x + 4

What is the inverse of f(x)=13-x^2,x>= 0 ?
The inverse of f(x)=13-x^2,x>= 0 is sqrt(-x+13),-sqrt(-x+13)