What is the inverse of f(x)=10ln(40t-1200) ?

The inverse of f(x)=10ln(40t-1200) is (e^{t/(10)}+1200)/(40)

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inverse of f(x)=10ln(40t-1200)

inverse

f (x) = 10 ln (40 t - 1200)

\frac{e ^{\frac{t}{10}} + 1200}{40}

Solution steps

x = 10 ln (40 t - 1200)

Replace

t

with

x

t = 10 ln (40 x - 1200)

Solve for

x, t = 10 ln (40 x - 1200)

\frac{e ^{\frac{t}{10}} + 1200}{40}

f (x) = lo g_{2} (2^{x})

- x - 2

y = 2 x + 1 - 3

3 4 x - 9

f (x) = 2 + e^{x}

What is the inverse of f(x)=10ln(40t-1200) ?
The inverse of f(x)=10ln(40t-1200) is (e^{t/(10)}+1200)/(40)