What is the inverse of f(x)=(x+5)^2,x>=-5 ?

The inverse of f(x)=(x+5)^2,x>=-5 is sqrt(x)-5,-sqrt(x)-5

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inverse of f(x)=(x+5)^2,x>=-5

inverse

f (x) = (x + 5)^{2}, x \geq - 5

x - 5, - x - 5

Solution steps

y = (x + 5)^{2}

Replace

x

with

y

x = (y + 5)^{2}

Solve for

y, x = (y + 5)^{2}

x - 5, - x - 5

p (x) = 2 x + 3

f (x) = lo g_{3} (x + 17)

y = x^{2} + x + 6

f (x) = \frac{3 x ^{2} + 5}{2}

f (x) = \frac{5 x - 2}{2 x - 2}

What is the inverse of f(x)=(x+5)^2,x>=-5 ?
The inverse of f(x)=(x+5)^2,x>=-5 is sqrt(x)-5,-sqrt(x)-5