What is the inverse of y=3log_{10}(x-1)+4 ?

The inverse of y=3log_{10}(x-1)+4 is 10^{(x-4)/3}+1

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inverse of y=3log_{10}(x-1)+4

inverse

y = 3 lo g_{10} (x - 1) + 4

1 0^{\frac{x - 4}{3}} + 1

Solution steps

y = 3 lo g_{10} (x - 1) + 4

Replace

x

with

y

x = 3 lo g_{10} (y - 1) + 4

Solve for

y, x = 3 lo g_{10} (y - 1) + 4

1 0^{\frac{x - 4}{3}} + 1

f (x) = \frac{9 - 5 cos ( 3 x )}{2}

f (x) = 13 - 3 x^{3}

f (x) = \frac{1}{6} x + 12

f (x) = \frac{( 2 x - 1 )}{x ( x - 1 )}

y = 3 + cos (x)

What is the inverse of y=3log_{10}(x-1)+4 ?
The inverse of y=3log_{10}(x-1)+4 is 10^{(x-4)/3}+1