What is the inverse of f(x)=x^2-13,x>= 0 ?

The inverse of f(x)=x^2-13,x>= 0 is sqrt(x+13),-sqrt(x+13)

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inverse of f(x)=x^2-13,x>= 0

inverse

f (x) = x^{2} - 13, x \geq 0

x + 13, - x + 13

Solution steps

y = x^{2} - 13

Replace

x

with

y

x = y^{2} - 13

Solve for

y, x = y^{2} - 13

x + 13, - x + 13

f (x) = 5 + 3 a x

f (x) = 2^{x - 2}

f (x) = 5 x - 4

2 x^{3} - 3

f (x) = \frac{x + 2}{9 x + 7}

What is the inverse of f(x)=x^2-13,x>= 0 ?
The inverse of f(x)=x^2-13,x>= 0 is sqrt(x+13),-sqrt(x+13)