What is the inverse of f(x)=4(pi)x^2 ?

The inverse of f(x)=4(pi)x^2 is (sqrt(pi)sqrt(x))/(2pi),-(sqrt(pi)sqrt(x))/(2pi)

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inverse of f(x)=4(pi)x^2

inverse

f (x) = 4 (π) x^{2}

\frac{π x}{2 π}, - \frac{π x}{2 π}

Solution steps

y = 4 π x^{2}

Replace

x

with

y

x = 4 π y^{2}

Solve for

y, x = 4 π y^{2}

\frac{π x}{2 π}, - \frac{π x}{2 π}

ln (x) + 2

y = 2^{3 x} - 4

f (x) = \frac{3 x + 6}{1 x - 3}

f (x) = \frac{( x + 3 )}{2 x + 5} a (x, t) t x = 3

f (x) = 10 - ln (x - 5)

What is the inverse of f(x)=4(pi)x^2 ?
The inverse of f(x)=4(pi)x^2 is (sqrt(pi)sqrt(x))/(2pi),-(sqrt(pi)sqrt(x))/(2pi)