What is the inverse of f(x)=(x-4)^2+2 ?

The inverse of f(x)=(x-4)^2+2 is sqrt(x-2)+4,-sqrt(x-2)+4

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inverse of f(x)=(x-4)^2+2

inverse

f (x) = (x - 4)^{2} + 2

x - 2 + 4, - x - 2 + 4

Solution steps

y = (x - 4)^{2} + 2

Replace

x

with

y

x = (y - 4)^{2} + 2

Solve for

y, x = (y - 4)^{2} + 2

x - 2 + 4, - x - 2 + 4

f (x) = \frac{x}{x + 2}

f (x) = x^{4} - 4

f (x) = x^{4} - 7

f (x) = \frac{( 3 x - 1 )}{2}

lo g_{3} (3 x + 4)

What is the inverse of f(x)=(x-4)^2+2 ?
The inverse of f(x)=(x-4)^2+2 is sqrt(x-2)+4,-sqrt(x-2)+4