What is the inverse of f(x)=(20+0.4x)/(100+x) ?

The inverse of f(x)=(20+0.4x)/(100+x) is (100(-5x+1))/(-2+5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(20+0.4x)/(100+x)

inverse

f (x) = \frac{20 + 0.4 x}{100 + x}

\frac{100 ( - 5 x + 1 )}{- 2 + 5 x}

Solution steps

y = \frac{20 + 0.4 x}{100 + x}

Replace

x

with

y

x = \frac{20 + 0.4 y}{100 + y}

Solve for

y, x = \frac{20 + 0.4 y}{100 + y}

\frac{100 ( - 5 x + 1 )}{- 2 + 5 x}

f (x) = \frac{3 3 x + 1}{5}

y = \frac{x + 1}{x - 1}

f (x) = \frac{8 x}{3 x - 4}

f (x) = \frac{1 - 2 x}{2 + x}

f (x) = \frac{5 x + 3}{x - 2}

What is the inverse of f(x)=(20+0.4x)/(100+x) ?
The inverse of f(x)=(20+0.4x)/(100+x) is (100(-5x+1))/(-2+5x)