What is the inverse of f(x)=A(r)=4(pi)r^2 ?

The inverse of f(x)=A(r)=4(pi)r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)

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inverse of f(x)=A(r)=4(pi)r^2

inverse

f (x) = A (r) = 4 (π) r^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

Solution steps

x = 4 π r^{2}

Replace

r

with

x

r = 4 π x^{2}

Solve for

x, r = 4 π x^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

2 + ln (x + 3)

f (x) = \frac{( 3 x - 2 )}{6}

y = - 2 x^{2} + 3 x

f (x) = \cdot + 2

f (x) = - 3 x + 13

What is the inverse of f(x)=A(r)=4(pi)r^2 ?
The inverse of f(x)=A(r)=4(pi)r^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)