What is the inverse of y=-2x^2+3x ?

The inverse of y=-2x^2+3x is -(-3+sqrt(9-8x))/4 ,-(-3-sqrt(9-8x))/4

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inverse of y=-2x^2+3x

inverse

y = - 2 x^{2} + 3 x

- \frac{- 3 + 9 - 8 x}{4}, - \frac{- 3 - 9 - 8 x}{4}

Solution steps

y = - 2 x^{2} + 3 x

Replace

x

with

y

x = - 2 y^{2} + 3 y

Solve for

y, x = - 2 y^{2} + 3 y

- \frac{- 3 + 9 - 8 x}{4}, - \frac{- 3 - 9 - 8 x}{4}

f (x) = \cdot + 2

f (x) = - 3 x + 13

cos (- 56 7^{\circ})

f (x) = \frac{( 4 x - 9 )}{5}

f (x) = tan (\frac{π x}{2})

What is the inverse of y=-2x^2+3x ?
The inverse of y=-2x^2+3x is -(-3+sqrt(9-8x))/4 ,-(-3-sqrt(9-8x))/4