What is the inverse of 1/4 (x-2)^2-2 ?

The inverse of 1/4 (x-2)^2-2 is 2sqrt(x+2)+2,-2sqrt(x+2)+2

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inverse of 1/4 (x-2)^2-2

inverse

\frac{1}{4} (x - 2)^{2} - 2

2 x + 2 + 2, - 2 x + 2 + 2

Solution steps

y = \frac{1}{4} (x - 2)^{2} - 2

Replace

x

with

y

x = \frac{1}{4} (y - 2)^{2} - 2

Solve for

y, x = \frac{1}{4} (y - 2)^{2} - 2

2 x + 2 + 2, - 2 x + 2 + 2

f (x) = - 5 x - 3

y = 2 x^{3} - 1

h (x) = \frac{1}{2} x - \frac{3}{7}

f (x) = n - 1

\frac{3 x + 1}{6}

What is the inverse of 1/4 (x-2)^2-2 ?
The inverse of 1/4 (x-2)^2-2 is 2sqrt(x+2)+2,-2sqrt(x+2)+2