What is the inverse of f(x)=2*pi*r^2+8*pi*r ?

The inverse of f(x)=2*pi*r^2+8*pi*r is (-8pi+sqrt(64pi^2+8pir))/(4pi),(-8pi-sqrt(64pi^2+8pir))/(4pi)

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inverse of f(x)=2pir^2+8pir

inverse

f (x) = 2 \cdot π \cdot r^{2} + 8 \cdot π \cdot r

\frac{- 8 π + 64 π ^{2} + 8 π r}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π r}{4 π}

Solution steps

x = 2 π r^{2} + 8 π r

Replace

r

with

x

r = 2 π x^{2} + 8 π x

Solve for

x, r = 2 \cdot π \cdot x^{2} + 8 \cdot π \cdot x

\frac{- 8 π + 64 π ^{2} + 8 π r}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π r}{4 π}

f (x) = \frac{2 x + 3}{3 x - 4}

f (x) = \frac{2 x + 3}{3 x - 6}

f (x) = 3 e^{x + 1}

h (x) = lo g_{10} (x + 1) - 3

+ 5 x + 4

What is the inverse of f(x)=2*pi*r^2+8*pi*r ?
The inverse of f(x)=2*pi*r^2+8*pi*r is (-8pi+sqrt(64pi^2+8pir))/(4pi),(-8pi-sqrt(64pi^2+8pir))/(4pi)