What is the inverse of g(x)=(2x+1)/(3x+4) ?

The inverse of g(x)=(2x+1)/(3x+4) is (1-4x)/(3x-2)

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inverse of g(x)=(2x+1)/(3x+4)

inverse

g (x) = \frac{2 x + 1}{3 x + 4}

\frac{1 - 4 x}{3 x - 2}

Solution steps

y = \frac{2 x + 1}{3 x + 4}

Replace

x

with

y

x = \frac{2 y + 1}{3 y + 4}

Solve for

y, x = \frac{2 y + 1}{3 y + 4}

\frac{1 - 4 x}{3 x - 2}

lo g_{a} (x)

f (x) = \frac{1000 ( 1.5 - x ) ^{2}}{3}

y = lo g_{6} (x)

y = \frac{3 x + 2}{x - 5}

2 sin (\frac{1}{3} x)

What is the inverse of g(x)=(2x+1)/(3x+4) ?
The inverse of g(x)=(2x+1)/(3x+4) is (1-4x)/(3x-2)