What is the inverse of f(x)=sqrt(y-y^2) ?

The inverse of f(x)=sqrt(y-y^2) is -(-1+sqrt(1-4y^2))/2 ,-(-1-sqrt(1-4y^2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(y-y^2)

inverse

f (x) = y - y^{2}

- \frac{- 1 + 1 - 4 y ^{2}}{2}, - \frac{- 1 - 1 - 4 y ^{2}}{2}

Solution steps

x = y - y^{2}

Replace

y

with

x

y = x - x^{2}

Solve for

x, y = x - x^{2}

- \frac{- 1 + 1 - 4 y ^{2}}{2}, - \frac{- 1 - 1 - 4 y ^{2}}{2}

- \frac{x + 5}{x - 6}

5 x - 25

f (x) = \frac{( 2 - x )}{3 x + 2}

f (x) = 0.66

- \frac{1}{2} x + 3, x \geq 3

What is the inverse of f(x)=sqrt(y-y^2) ?
The inverse of f(x)=sqrt(y-y^2) is -(-1+sqrt(1-4y^2))/2 ,-(-1-sqrt(1-4y^2))/2