What is the inverse of f(x)=x-9/x ?

The inverse of f(x)=x-9/x is (x+sqrt(x^2+36))/2 ,(x-sqrt(x^2+36))/2

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inverse of f(x)=x-9/x

inverse

f (x) = x - \frac{9}{x}

\frac{x + x ^{2} + 36}{2}, \frac{x - x ^{2} + 36}{2}

Solution steps

y = x - \frac{9}{x}

Replace

x

with

y

x = y - \frac{9}{y}

Solve for

y, x = y - \frac{9}{y}

\frac{x + x ^{2} + 36}{2}, \frac{x - x ^{2} + 36}{2}

f (x) = \frac{1 - e ^{6 x}}{1 + e ^{6 x}}

\frac{2 x + 1}{x - 6}

f (x) = x^{2}, x < 0

f (x) = 5 \cdot 12 5^{2}

2 + t^{2}

What is the inverse of f(x)=x-9/x ?
The inverse of f(x)=x-9/x is (x+sqrt(x^2+36))/2 ,(x-sqrt(x^2+36))/2