What is the inverse of f(x)=(-16x+13)^2 ?

The inverse of f(x)=(-16x+13)^2 is -(sqrt(x)-13)/(16),-(-sqrt(x)-13)/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(-16x+13)^2

inverse

f (x) = (- 16 x + 13)^{2}

- \frac{x - 13}{16}, - \frac{- x - 13}{16}

Solution steps

y = (- 16 x + 13)^{2}

Replace

x

with

y

x = (- 16 y + 13)^{2}

Solve for

y, x = (- 16 y + 13)^{2}

- \frac{x - 13}{16}, - \frac{- x - 13}{16}

3 x^{3} - 8

y = (x + 8)^{3}

3^{x + 4}

f (x) = 53 + 4.7 x

f (x) = \frac{x}{1 - 2 x}

What is the inverse of f(x)=(-16x+13)^2 ?
The inverse of f(x)=(-16x+13)^2 is -(sqrt(x)-13)/(16),-(-sqrt(x)-13)/(16)