What is the inverse of (x^2)/(x^2-1) ?

The inverse of (x^2)/(x^2-1) is sqrt(x/(x-1)),-sqrt(x/(x-1))

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inverse of (x^2)/(x^2-1)

inverse

\frac{x ^{2}}{x ^{2} - 1}

\frac{x}{x - 1}, - \frac{x}{x - 1}

Solution steps

y = \frac{x ^{2}}{x ^{2} - 1}

Replace

x

with

y

x = \frac{y ^{2}}{y ^{2} - 1}

Solve for

y, x = \frac{y ^{2}}{y ^{2} - 1}

\frac{x}{x - 1}, - \frac{x}{x - 1}

f (x) = 5 x^{2} + 10 x + 20

f (x) = 3.2

f (x) = \frac{x + 3}{x + 8}

f (x) = x - 5 - 2

f (x) = x - 5 - 5

What is the inverse of (x^2)/(x^2-1) ?
The inverse of (x^2)/(x^2-1) is sqrt(x/(x-1)),-sqrt(x/(x-1))