What is the inverse of f(x)= 8/(7+x^2) ?

The inverse of f(x)= 8/(7+x^2) is sqrt((8-7x)/x),-sqrt((8-7x)/x)

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inverse of f(x)= 8/(7+x^2)

inverse

f (x) = \frac{8}{7 + x ^{2}}

\frac{8 - 7 x}{x}, - \frac{8 - 7 x}{x}

Solution steps

y = \frac{8}{7 + x ^{2}}

Replace

x

with

y

x = \frac{8}{7 + y ^{2}}

Solve for

y, x = \frac{8}{7 + y ^{2}}

\frac{8 - 7 x}{x}, - \frac{8 - 7 x}{x}

f (x) = 9 - 2 x^{2}

f (x) = 2.6

f (x) = - 2 x + 4 + 1

\frac{2}{x ^{4} + 4 x ^{2} + 2}

f (x) = - \frac{x + 1}{2}

What is the inverse of f(x)= 8/(7+x^2) ?
The inverse of f(x)= 8/(7+x^2) is sqrt((8-7x)/x),-sqrt((8-7x)/x)