What is the inverse of f(x)=(((x-3))/8)^{1/3} ?

The inverse of f(x)=(((x-3))/8)^{1/3} is 8x^3+3

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inverse of f(x)=(((x-3))/8)^{1/3}

inverse

f (x) = (\frac{( x - 3 )}{8})^{\frac{1}{3}}

8 x^{3} + 3

Solution steps

y = (\frac{x - 3}{8})^{\frac{1}{3}}

Replace

x

with

y

x = (\frac{y - 3}{8})^{\frac{1}{3}}

Solve for

y, x = (\frac{y - 3}{8})^{\frac{1}{3}}

8 x^{3} + 3

\frac{2 X}{X + 3}

f (x) = \frac{x + 1}{x - 2}

5 x^{2} - \frac{6}{7}

g (x) = x^{2} + 2

f (x) = 3 x^{2} + 2 y^{2} - 6 x - 12 y + 15 = 0

What is the inverse of f(x)=(((x-3))/8)^{1/3} ?
The inverse of f(x)=(((x-3))/8)^{1/3} is 8x^3+3