What is the inverse of y=e^{(x^2-2x)} ?

The inverse of y=e^{(x^2-2x)} is 1+sqrt(ln(x)+1),1-sqrt(ln(x)+1)

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inverse of y=e^{(x^2-2x)}

inverse

y = e^{(x^{2} - 2 x)}

1 + ln (x) + 1, 1 - ln (x) + 1

Solution steps

y = e^{x^{2} - 2 x}

Replace

x

with

y

x = e^{y^{2} - 2 y}

Solve for

y, x = e^{y^{2} - 2 y}

1 + ln (x) + 1, 1 - ln (x) + 1

f (x) = \frac{x ^{2} - 3 x}{1 - x ^{2}}

\frac{3 x - 7}{4 x + 3}

f (x) = 4 5 x + 3 - 3

lo g_{e} (x)

f (x) = arccot (- 3)

What is the inverse of y=e^{(x^2-2x)} ?
The inverse of y=e^{(x^2-2x)} is 1+sqrt(ln(x)+1),1-sqrt(ln(x)+1)