What is the inverse of g(x)=2x^2-8 ?

The inverse of g(x)=2x^2-8 is sqrt((x+8)/2),-sqrt((x+8)/2)

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inverse of g(x)=2x^2-8

inverse

g (x) = 2 x^{2} - 8

\frac{x + 8}{2}, - \frac{x + 8}{2}

Solution steps

y = 2 x^{2} - 8

Replace

x

with

y

x = 2 y^{2} - 8

Solve for

y, x = 2 y^{2} - 8

\frac{x + 8}{2}, - \frac{x + 8}{2}

f (x) = \frac{( x + 5 )}{2}

2 + \frac{- 3}{x + 2}

\frac{6}{x ^{2} - 4}

f (x) = \frac{s - 3}{5 s - 3}

14 ln (tan (x))

What is the inverse of g(x)=2x^2-8 ?
The inverse of g(x)=2x^2-8 is sqrt((x+8)/2),-sqrt((x+8)/2)