What is the inverse of f(x)=(x+3)^2+5 ?

The inverse of f(x)=(x+3)^2+5 is sqrt(x-5)-3,-sqrt(x-5)-3

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inverse of f(x)=(x+3)^2+5

inverse

f (x) = (x + 3)^{2} + 5

x - 5 - 3, - x - 5 - 3

Solution steps

y = (x + 3)^{2} + 5

Replace

x

with

y

x = (y + 3)^{2} + 5

Solve for

y, x = (y + 3)^{2} + 5

x - 5 - 3, - x - 5 - 3

18500 (0.16 - r^{2})

f (x) = - ln (1 - x)

3 x + 7

f (x) = sin (x + 1)

What is the inverse of f(x)=(x+3)^2+5 ?
The inverse of f(x)=(x+3)^2+5 is sqrt(x-5)-3,-sqrt(x-5)-3