What is the inverse of f(x)=4cos(x/3),3pi<= x<= 6pi ?

The inverse of f(x)=4cos(x/3),3pi<= x<= 6pi is 3arccos(x/4)

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inverse of f(x)=4cos(x/3),3pi<= x<= 6pi

inverse

f (x) = 4 cos (\frac{x}{3}), 3 π \leq x \leq 6 π

3 arccos (\frac{x}{4})

Solution steps

Solve for

cos (\frac{x}{3}), y = 4 cos (\frac{x}{3})

cos (\frac{x}{3}) = \frac{y}{4}

cos (a) = b \Rightarrow a = arccos (b)

\frac{x}{3} = arccos (\frac{y}{4})

Solve for

x, \frac{x}{3} = arccos (\frac{y}{4})

3 arccos (\frac{y}{4})

Substitute

y = x

3 arccos (\frac{x}{4})

lo g_{3} (9 - x) + 2

\frac{x + 2}{7}

8 - x^{2}

f (x) = \frac{x + 1}{x + 5}

f (x) = 3 - 2 (x - 4) - 3

What is the inverse of f(x)=4cos(x/3),3pi<= x<= 6pi ?
The inverse of f(x)=4cos(x/3),3pi<= x<= 6pi is 3arccos(x/4)