What is the inverse of f(x)=4sqrt(x-3)-5 ?

The inverse of f(x)=4sqrt(x-3)-5 is (x^2+25}{16}+\frac{5x)/8+3

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inverse of f(x)=4sqrt(x-3)-5

inverse

f (x) = 4 x - 3 - 5

\frac{x ^{2} + 25}{16} + \frac{5 x}{8} + 3

Solution steps

y = 4 x - 3 - 5

Replace

x

with

y

x = 4 y - 3 - 5

Solve for

y, x = 4 y - 3 - 5

\frac{x ^{2} + 25}{16} + \frac{5 x}{8} + 3

4 x^{2} + 34 x

7 - 4 x^{3}

f (L) = 124.5 + 45 L - 0.03 L^{2}

f (x) = \frac{2 x + 3}{5 - 6 x}

f (x) = \frac{9 x}{4 x - 5}

What is the inverse of f(x)=4sqrt(x-3)-5 ?
The inverse of f(x)=4sqrt(x-3)-5 is (x^2+25}{16}+\frac{5x)/8+3