What is the inverse of f(x)=\sqrt[5]{(x-1)/2} ?

The inverse of f(x)=\sqrt[5]{(x-1)/2} is 2x^5+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{(x-1)/2}

inverse

f (x) = 5 \frac{x - 1}{2}

2 x^{5} + 1

Solution steps

y = 5 \frac{x - 1}{2}

Replace

x

with

y

x = 5 \frac{y - 1}{2}

Solve for

y, x = 5 \frac{y - 1}{2}

2 x^{5} + 1

f (x) = 70 e^{- 0.0009 x}

\frac{5}{x - 1} + 3

f (x) = \frac{( 2 x + 3 )}{4 x + 4}

f (x) = \frac{( 15 - 2 x )}{3}

f (x) = \frac{x}{9}

What is the inverse of f(x)=\sqrt[5]{(x-1)/2} ?
The inverse of f(x)=\sqrt[5]{(x-1)/2} is 2x^5+1