What is the inverse of f(x)=((x-3)/2)^2 ?

The inverse of f(x)=((x-3)/2)^2 is 2sqrt(x)+3,-2sqrt(x)+3

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inverse of f(x)=((x-3)/2)^2

inverse

f (x) = (\frac{x - 3}{2})^{2}

2 x + 3, - 2 x + 3

Solution steps

y = (\frac{x - 3}{2})^{2}

Replace

x

with

y

x = (\frac{y - 3}{2})^{2}

Solve for

y, x = (\frac{y - 3}{2})^{2}

2 x + 3, - 2 x + 3

\frac{x}{5}

2 e^{- 3 x} + 4

f (x) = \frac{1}{2 π} e^{- \frac{1 x ^{2}}{2}}

f (x) = \frac{1 - 3 x}{x + 2}

f (x) = 9000 \cdot x

What is the inverse of f(x)=((x-3)/2)^2 ?
The inverse of f(x)=((x-3)/2)^2 is 2sqrt(x)+3,-2sqrt(x)+3