What is the inverse of f(x)=9x^2+4 ?

The inverse of f(x)=9x^2+4 is (sqrt(x-4))/3 ,-(sqrt(x-4))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=9x^2+4

inverse

f (x) = 9 x^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

Solution steps

y = 9 x^{2} + 4

Replace

x

with

y

x = 9 y^{2} + 4

Solve for

y, x = 9 y^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

y = 3 x^{2} + 12 x - 7

f (x) = ln (1 - x)

1.2

f (x) = 2^{10 x}

f (x) = x + 5 - 4

What is the inverse of f(x)=9x^2+4 ?
The inverse of f(x)=9x^2+4 is (sqrt(x-4))/3 ,-(sqrt(x-4))/3