What is the inverse of (\sqrt[3]{x^2})/2+1 ?

The inverse of (\sqrt[3]{x^2})/2+1 is sqrt(8x^3-24x^2+24x-8),-sqrt(8x^3-24x^2+24x-8)

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inverse of (\sqrt[3]{x^2})/2+1

inverse

8 x^{3} - 24 x^{2} + 24 x - 8, - 8 x^{3} - 24 x^{2} + 24 x - 8

Solution steps

Replace

x

with

y

Solve for

8 x^{3} - 24 x^{2} + 24 x - 8, - 8 x^{3} - 24 x^{2} + 24 x - 8

f (x) = 12 + 6 x - 6

\frac{x ^{4}}{4}

f (t) = 28.4 e^{0.01 t}

\frac{5}{x + 8}

What is the inverse of (\sqrt[3]{x^2})/2+1 ?
The inverse of (\sqrt[3]{x^2})/2+1 is sqrt(8x^3-24x^2+24x-8),-sqrt(8x^3-24x^2+24x-8)