What is the inverse of f(x)=-3(y-1)^2+2 ?

The inverse of f(x)=-3(y-1)^2+2 is sqrt(-(y-2)/3)+1,-sqrt(-(y-2)/3)+1

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inverse of f(x)=-3(y-1)^2+2

inverse

f (x) = - 3 (y - 1)^{2} + 2

- \frac{y - 2}{3} + 1, - - \frac{y - 2}{3} + 1

Solution steps

x = - 3 (y - 1)^{2} + 2

Replace

y

with

x

y = - 3 (x - 1)^{2} + 2

Solve for

x, y = - 3 (x - 1)^{2} + 2

- \frac{y - 2}{3} + 1, - - \frac{y - 2}{3} + 1

x + 2 - 7

cos (- 53786 5^{\circ})

f (x) = 2 (x - 2) 2 = 8 (7 + y)

f (x) = \frac{6 x + 5}{5 x - 3}

f (x) = \frac{( 10 + 4 x )}{5 x + 6}

What is the inverse of f(x)=-3(y-1)^2+2 ?
The inverse of f(x)=-3(y-1)^2+2 is sqrt(-(y-2)/3)+1,-sqrt(-(y-2)/3)+1