What is the inverse of f(x)=(2-x^2)/7 ?

The inverse of f(x)=(2-x^2)/7 is sqrt(-7x+2),-sqrt(-7x+2)

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inverse of f(x)=(2-x^2)/7

inverse

f (x) = \frac{2 - x ^{2}}{7}

- 7 x + 2, - - 7 x + 2

Solution steps

y = \frac{2 - x ^{2}}{7}

Replace

x

with

y

x = \frac{2 - y ^{2}}{7}

Solve for

y, x = \frac{2 - y ^{2}}{7}

- 7 x + 2, - - 7 x + 2

f (x) = \frac{1}{x ^{2} - 9}

f (x) = 2 (x - 3)^{2} - 8

f (x) = \frac{e ^{- x}}{( 1 + e ^{- x} ) ^{2}}

+ lo g_{8} (x)

f (x) = \frac{1}{2 ( x - 4 ) ^{2} + 1}

What is the inverse of f(x)=(2-x^2)/7 ?
The inverse of f(x)=(2-x^2)/7 is sqrt(-7x+2),-sqrt(-7x+2)