What is the inverse of y=2sqrt((3x+1))+4 ?

The inverse of y=2sqrt((3x+1))+4 is (-8x+x^2+12)/(12)

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inverse of y=2sqrt((3x+1))+4

inverse

y = 2 (3 x + 1) + 4

\frac{- 8 x + x ^{2} + 12}{12}

Solution steps

y = 2 3 x + 1 + 4

Replace

x

with

y

x = 2 3 y + 1 + 4

Solve for

y, x = 2 3 y + 1 + 4

\frac{- 8 x + x ^{2} + 12}{12}

f (x) = ln (x^{59})

f (x) = \frac{2}{lo g _{3} ( x )}

\frac{x ^{2} + 1}{x}

f (x) = \frac{1}{x ^{2} - x}

f (x) = \frac{3 x}{x - 3}

What is the inverse of y=2sqrt((3x+1))+4 ?
The inverse of y=2sqrt((3x+1))+4 is (-8x+x^2+12)/(12)