What is the inverse of y=ln(x+sqrt(x^2+1)) ?

The inverse of y=ln(x+sqrt(x^2+1)) is -(1-e^{2x})/(2e^x)

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inverse of y=ln(x+sqrt(x^2+1))

inverse

y = ln (x + x^{2} + 1)

- \frac{1 - e ^{2 x}}{2 e ^{x}}

Solution steps

y = ln (x + x^{2} + 1)

Replace

x

with

y

x = ln (y + y^{2} + 1)

Solve for

y, x = ln (y + y^{2} + 1)

- \frac{1 - e ^{2 x}}{2 e ^{x}}

5^{2 x + 7}

g (x) = x - 3

f (x) = lo g_{2} (5 x)

f (x) = 5 x^{2} - x^{4}

f (x) = \frac{5}{2 - x}, x \neq = 2

What is the inverse of y=ln(x+sqrt(x^2+1)) ?
The inverse of y=ln(x+sqrt(x^2+1)) is -(1-e^{2x})/(2e^x)