What is the inverse of f(x)=sqrt(x^2-4),x>= 2 ?

The inverse of f(x)=sqrt(x^2-4),x>= 2 is sqrt(x^2+4),-sqrt(x^2+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(x^2-4),x>= 2

inverse

f (x) = x^{2} - 4, x \geq 2

x^{2} + 4, - x^{2} + 4

Solution steps

y = x^{2} - 4

Replace

x

with

y

x = y^{2} - 4

Solve for

y, x = y^{2} - 4

x^{2} + 4, - x^{2} + 4

f (x) = \frac{1 - e ^{- x}}{1 + e ^{x}}

3 - x + 8

f (x) = 600 e^{x} + 2022

sin (\frac{25}{12.21})

What is the inverse of f(x)=sqrt(x^2-4),x>= 2 ?
The inverse of f(x)=sqrt(x^2-4),x>= 2 is sqrt(x^2+4),-sqrt(x^2+4)