What is the inverse of f(x)=(1-x^2)^{1/3} ?

The inverse of f(x)=(1-x^2)^{1/3} is sqrt(-x^3+1),-sqrt(-x^3+1)

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inverse of f(x)=(1-x^2)^{1/3}

inverse

f (x) = (1 - x^{2})^{\frac{1}{3}}

- x^{3} + 1, - - x^{3} + 1

Solution steps

y = (1 - x^{2})^{\frac{1}{3}}

Replace

x

with

y

x = (1 - y^{2})^{\frac{1}{3}}

Solve for

y, x = (1 - y^{2})^{\frac{1}{3}}

- x^{3} + 1, - - x^{3} + 1

0.4 x + 6.6

f (x) = arctan (x^{2} - \frac{π}{4})

f (x) = \frac{3}{- 3 x + 2}

f (x) = x^{2} - 4

f (x) = \frac{( x + 2 )}{- 2 x + 1}

What is the inverse of f(x)=(1-x^2)^{1/3} ?
The inverse of f(x)=(1-x^2)^{1/3} is sqrt(-x^3+1),-sqrt(-x^3+1)